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26) Find the middle terms of the sequence formed by all numbers between 9 and 95, which leavea remainder 1 when divided by 3. Also, find the sum of the numbers on both sides of themiddle term separately |
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Answer» Numbers between 9 and 95 is in APSo first term a = 10,Common difference = 11-10 = 1Total number of terms = 85Middle term = (85 + 1)/2= 86/2 = 43 rd term Value of middle term= a + 42d= 10 + 42*1 = 52 Sum of terms left of 52= 42/2(10 + 51)= 21(61) = 1280 Sum of terms right of 52= 42/2(53 + 94)= 21(147) = 3087 |
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