(265) Find two part of 40 such that the sum of their squares is 850. – InterviewSolution

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1.

(265) Find two part of 40 such that the sum of their squares is 850.

Answer»

Let one part of 40 be x

Another part is 40-x

x²+(40-x)² = 850

x²+40²+x²-80x = 850

2x²-80x = 850-1600

2x²-80x+750 = 0

x = 80 +- √(-80)²+4*2*750 / 2*2

= 80 +- √6400 + 6000 /4

= 80 +- √12400/4

= 80+- √3100

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