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27 g of Al (at mass=27) will react completely with oxygen equal to |
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Answer» 24 g `4Al + 3O_(2) to 2Al_(2)O_(3)` therefore 108 g of AI reacts with 96g of `O_(2)`. therefore 27G of AI with react with `=(96 XX 27)/(108)` = 24 g of `CO_(2)` |
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