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`27 g` of `Al` will react completely with…… `g` of `O_(2)`A. (a)8 gB. (b)16 gC. (c )32 gD. (d)24 g |
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Answer» Correct Answer - D `4 Al+3O_(2)rarr2Al_(2)O_(3)` At. Wt. of `Al=27` Thus `4xx27 g` of Al reacts with oxygen`=3xx32 g` `:. 27 g` of Al reacts will oxygen`=(3xx32)/(4xx27)xx27=24 g`. |
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