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27 p ^ { 3 } - \frac { 1 } { 216 } - \frac { 9 p ^ { 2 } } { 2 } + \frac { p } { 4 } |
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Answer» 27p^3- 1/216 - 9/2p^2+1/4p (3p)^3-(1/6)^3- 3(3p)^2(1/6) + 3(3p)(1/6)^2 (3p - 1/6)^3= (3p - 1/6)(3p - 1/6)(3p - 1/6) thanks Yar , but I was just testing the app |
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