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2८ 5 1o YA M—EL M 5 हु -स्डत्थ, लत |
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Answer» Let a , d are first term and common difference of an A.Pnth term = Last term = a + ( n - 1 )d an = a + ( n - 1 )d Now , It is given that , Third term = 12 a + 2d = 12 ------( 1 ) Last term = 106 a + 49d = 106 ---( 2 ) Subtract ( 1 ) from ( 2 ) , we get 47d = 94 d = 2 Substitute d value in equation ( 1 ) , We get a + 2 × 2 = 12 a = 12 - 4 a = 8 29th term = a + 28d a29 = 8 + 28 × 2 = 8 + 56 = 64 |
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