1.

28 g of `N_(20 and 6g of H_(2)` were keip at `40^(@)C` in 1 litre vesscel the equilibrium mixture contained `24.54g` of `NH_(3).` The approximate value of `K_(c)`for the above reaction can be (in `"mole" ^(-2) "litre"^(2)`A. 75B. 50C. 25D. 100

Answer» Correct Answer - A
`N_(2)+3H_(2)hArr 2NH_(3)`
`{:("Initial conc.",1,3,0),("at equlibrium",1-0.81,3-2.43,1.62),(,0.19,0.57,):}`
No. of moles of `N_(2)=28/28=3` mole
No. of moles of `H_(2)=6/2=3` moles
`K_(c)=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))=([1.62]^(2))/([0.19][0.57]^(3))=75`


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