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The equlibrium concentration of X,Y and `YX_(2),` are 4,2 and 2 moles respectively for the equlibrium `2X+Y hArr YX_(2).` The value of `K_(c)` isA. `0.625`B. `2.0625`C. `6.25`D. `0.00625` |
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Answer» Correct Answer - B `K_(c)=([YX_(2)])/([X]^(2)[Y])=(2)/(4xx4xx2)=1/16=0.0625.` |
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