28 g of nitrogen and 6 g of hydrogen were mixed in a 1 litre closed container. At equilibrium 17 g NH_(3) was produced. Calculate the weight of nitrogen, hydrogen at equilibrium.

28 g of nitrogen and 6 g of hydrogen were mixed in a 1 litre closed co

1.	28 g of nitrogen and 6 g of hydrogen were mixed in a 1 litre closed container. At equilibrium 17 g NH_(3) was produced. Calculate the weight of nitrogen, hydrogen at equilibrium.
Answer» SOLUTION :GIVEN`m_(N_(2))=28G,m_(H_(2))=6g,` `V=1L` `(n_(N_(2)))_("INITIAL")=(28)/(28)="1 mol"` `(n_(H_(2)))_("Initial")=6/2=3" mol"` `N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)` `[NH_(3)]=((17)/(17))="1 mol"` Weight of `N_(2)` = (no. of moles of `N_(2)` ) `xx` molar mass of `N_(2)` `=0.5xx28=14g` Weight of `H_(2)` = (no. of moles of `H_(2)` ) `xx` molar mass of `H_(2)` `=1.5xx2=3g`