1.

28. If current I1=3Asinwt and I2=4Acoswt then I3 is: 1)5Asin(wt+53) 2)5Asin(wt+37) 3)5Asin(wt+45) 4)5Asin(wt+30)

Answer» 28. If current I1=3Asinwt and I2=4Acoswt then I3 is: 1)5Asin(wt+53) 2)5Asin(wt+37) 3)5Asin(wt+45) 4)5Asin(wt+30)


Discussion

No Comment Found