28. On annual day of a school, 400 students participated in the functi

1.	28. On annual day of a school, 400 students participated in the function. Frequency distribution showingtheir ages is as shown in the following tableAges (in years) 05-07 07-09 09-11 11-13 13-15 15-17 17-19Number of students70120 32 100 4528Find mean and median of the above data.
Answer» Here, the summation of Fi is equal to 400 and summation of FiDi is equal to -732. Hence, the mean is equal to 12- 732/400 = 10.17 . Therefore, the median is equal to 9 + ( 10/32) * 2 which is equal to 9.625. The median class is 9-11. Median is 9.625.

28. On annual day of a school, 400 students participated in the function. Frequency distribution showingtheir ages is as shown in the following tableAges (in years) 05-07 07-09 09-11 11-13 13-15 15-17 17-19Number of students70120 32 100 4528Find mean and median of the above data.

Answer»

Here, the summation of Fi is equal to 400 and summation of FiDi is equal to -732. Hence, the mean is equal to 12- 732/400 = 10.17 .

Therefore, the median is equal to 9 + ( 10/32) * 2 which is equal to 9.625. The median class is 9-11. Median is 9.625.