1.

29.2% W/w HCL stock solution has a density of 1.150 per millilitre the molar mass of HCL is 36.5 the volume in ML of stock solution required to prepare a 460 ML of solution of 0.4 MHCL is

Answer»

Molarity of stock solution (SOLN.) of HCl= (Molar mass)(%mass)(Density ofsolution)(10) 36.5(29.2)(1.25)(10) =10MAccording to dilution EQUATION M i V i =M F V f V i = M i M f V f = (10M)(0.4M)(200ML) =8mL.



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