InterviewSolution
Saved Bookmarks
| 1. |
29.2% W/w HCL stock solution has a density of 1.150 per millilitre the molar mass of HCL is 36.5 the volume in ML of stock solution required to prepare a 460 ML of solution of 0.4 MHCL is |
|
Answer» Molarity of stock solution (SOLN.) of HCl= (Molar mass)(%mass)(Density ofsolution)(10) 36.5(29.2)(1.25)(10) =10MAccording to dilution EQUATION M i V i =M F V f V i = M i M f V f = (10M)(0.4M)(200ML) =8mL. |
|