29.The radĂź of circular ends of a bucket of height 24 cm are 15 cm

1.	29.The radĂź of circular ends of a bucket of height 24 cm are 15 cm and 5 am. Find the area of its curvedsurface.DE 20men
Answer» Given: Height = 24 cm Radius 1 = 5 cm Radius 2 = 15 cm To find: Curved surface area. Solution: By formula, Curved surface area = π * Length * ( Radius 1 + Radius 2 ) Here, Length = √ ( Height + ( Radius 2 - Radius 1 )^2 ) Substituting, √ ( 24 + ( 15 - 5 )^2 ) Length = 11 cm Hence, 3.14 * 11 * ( 15 + 5 ) Curved surface area = 690 sq.cm

29.The radĂź of circular ends of a bucket of height 24 cm are 15 cm and 5 am. Find the area of its curvedsurface.DE 20men

Answer»

Given:

Height = 24 cm

Radius 1 = 5 cm

Radius 2 = 15 cm

To find:

Curved surface area.

Solution:

By formula,

Curved surface area = π * Length * ( Radius 1 + Radius 2 )

Here,

Length = √ ( Height + ( Radius 2 - Radius 1 )^2 )

Substituting,

√ ( 24 + ( 15 - 5 )^2 )

Length = 11 cm

Hence,

3.14 * 11 * ( 15 + 5 )

Curved surface area = 690 sq.cm