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290. A body of mass 5 kg is moving with a velocity of 10 m/s along a surface. The resistance by thesurface is 20 N. The body will stop after.A.10 mD. 12B. 12.5 mC. 15.5 m |
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Answer» ONG>ANSWER: M=5kg a= t v−u
1 V−10
f=20N f=m×a 20N=5kg×(V−10) 4=(v−10) v=14 Explanation: HOPE it is helpful to you.. plz follow me |
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