298 K of N_2O_(4(g)) hArr 2NO_(2(g))reaction is in equilibrium K_p = 0.14 atm. Calculate of K_c (R=0.082 L atm K^(-1) "mol"^(-1))

298 K of N_2O_(4(g)) hArr 2NO_(2(g))reaction is in equilibrium K_p = 0

1.	298 K of N_2O_(4(g)) hArr 2NO_(2(g))reaction is in equilibrium K_p = 0.14 atm. Calculate of K_c (R=0.082 L atm K^(-1) "mol"^(-1))
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`5.73xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>)`M</body></html>