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`2H_(2) O_(2) (l) rarr 2H_(2)o(l) + O_(2) (g)` `100 mL` of `X` molar `H_(2)O_(2)` gives `3L` of `O_(2)` gas under the condition when 1 moe occupies `24 L`. The value of `X` isA. 2.5B. 1C. 0.5D. 0.25 |
Answer» Correct Answer - D `2H_(2)O_(2) (l) rarr 2H_(2) P (l) + O_(2) (g)` `24 L O_(2) = 1 "mol" O_(2)` `3 L O_(2) = (1)/(8) "mol" O_(2) = (1)/(4) "mol" H_(2)O_(2) "in" mL` `2.5 "mol" H_(2) O_(2) L^(-1)` |
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