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2H2O ⇄ H3O+ + OH-,KW=1x10-14 at 25°C hence Ka is: |
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Answer» Molar mass of water = 18 gmol^-1 Mass of 1L water is 1000g Hence molarity of water [H2O]= 1000/18 molL^-1 Now dissociation constant of water Ka = [H+][OH-]/[H2O] = Kw/[H2O] = 10^-14×18/1000=18×10^-17 |
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