1.

`2HgtoHg_(2)^(++),E^(@)=+0.855V` `HgtoHg^(2+),E^(@)=0.799V` Equilibrium constant for the reaction `Hg+Hg^(2+)toHg_(2)^(++)` at `27^(@)C` isA. 89B. 82.3C. 79D. none of these

Answer» Correct Answer - C
`E^(@)` for the given reaction
`=0.855-0.799=0.056V`
`E_(cell)^(@)=(0.0591)/(2)"log"K_(c)`
or `logK_(c)=(0.056xx2)/(0.059)=1.8983`
`K_(c)`=Antilog `1.8983=79:12=79`


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