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`2HgtoHg_(2)^(++),E^(@)=+0.855V` `HgtoHg^(2+),E^(@)=0.799V` Equilibrium constant for the reaction `Hg+Hg^(2+)toHg_(2)^(++)` at `27^(@)C` isA. 89B. 82.3C. 79D. none of these |
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Answer» Correct Answer - C `E^(@)` for the given reaction `=0.855-0.799=0.056V` `E_(cell)^(@)=(0.0591)/(2)"log"K_(c)` or `logK_(c)=(0.056xx2)/(0.059)=1.8983` `K_(c)`=Antilog `1.8983=79:12=79` |
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