2KCI2MgMgOFind9 mo53.)In the following reaction,CaCO3 +2HCI CaCh +H20+

1.	2KCI2MgMgOFind9 mo53.)In the following reaction,CaCO3 +2HCI CaCh +H20+CO2when 10g CaCO3 is reacted with 10gHCl,2.2g CO2 is obtained. Find the percentyield of COz(1) 25%(3) 100%50%75%(4)
Answer» Here moles of CaCO3 is 10/100 = 0.1 moles and moles of HCl = 10/36.5 , which is greater than CaCO3 so, CaCO3 is the limiting reagent now , for 0.1 mole of CaCO3 , 0.1 mol of CO2 aill be formed having weight = 0.1*(44) = 4.4g .. theoretically. but actually 2.2g is yielded so, % yield =2.2/4.4× 100 = 50%

2KCI2MgMgOFind9 mo53.)In the following reaction,CaCO3 +2HCI CaCh +H20+CO2when 10g CaCO3 is reacted with 10gHCl,2.2g CO2 is obtained. Find the percentyield of COz(1) 25%(3) 100%50%75%(4)

Answer»

Here moles of CaCO3 is 10/100 = 0.1 moles and moles of HCl = 10/36.5 , which is greater than CaCO3 so, CaCO3 is the limiting reagent

now , for 0.1 mole of CaCO3 , 0.1 mol of CO2 aill be formed having weight = 0.1*(44) = 4.4g .. theoretically.

but actually 2.2g is yielded

so, % yield =2.2/4.4× 100 = 50%