1.

2kg of ice at `20^[email protected]` is mixed with 5kg of water at `20^[email protected]` in an insulating vessel having a negligible heat capacity. Calculate the final mass of water remaining in the container. It is given that the specific heats of water & ice are `1kcal//kg//^@C 0.5` `kcal//kg//^@C` while the latent heat of fusion of ice is `80kcal//kg`A. `7kg`B. `5kg`C. `4kg`D. `2kg`

Answer» Correct Answer - B
(b) Heat required to convert 5 kg of water at `20^@C` to 5kg of
water at `0^@C`
`=mC_(omega)DeltaT=5xx1xx20=100kcal`
Heat released by 2kg. Ice at `-20^@C` to convert into 2kg
of ice at `0^@C`
`=mC_(ice)DeltaT=2xx0.5xx20=20kcal.`
How much ice at `0^@C` will convert into water at `0^@C` for
giving another 80 kcal of heat
`Q=mL rArr 80=mxx80`
`rArr m=1kg`
Therefore the amount of water at `0^@C`
`=5kg+1kg=6kg`
Thus, at equilibrium, we have, [6 kg water at `0^@C`+1kg
ice at `0^@C`].


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