InterviewSolution
Saved Bookmarks
| 1. |
2kg of ice at `20^[email protected]` is mixed with 5kg of water at `20^[email protected]` in an insulating vessel having a negligible heat capacity. Calculate the final mass of water remaining in the container. It is given that the specific heats of water & ice are `1kcal//kg//^@C 0.5` `kcal//kg//^@C` while the latent heat of fusion of ice is `80kcal//kg`A. `7kg`B. `5kg`C. `4kg`D. `2kg` |
|
Answer» Correct Answer - B (b) Heat required to convert 5 kg of water at `20^@C` to 5kg of water at `0^@C` `=mC_(omega)DeltaT=5xx1xx20=100kcal` Heat released by 2kg. Ice at `-20^@C` to convert into 2kg of ice at `0^@C` `=mC_(ice)DeltaT=2xx0.5xx20=20kcal.` How much ice at `0^@C` will convert into water at `0^@C` for giving another 80 kcal of heat `Q=mL rArr 80=mxx80` `rArr m=1kg` Therefore the amount of water at `0^@C` `=5kg+1kg=6kg` Thus, at equilibrium, we have, [6 kg water at `0^@C`+1kg ice at `0^@C`]. |
|