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2Sh*4 + cosA = 1 |
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Answer» F(x) = sin^2(x) + cos^2(x) f '(x) = 2 sin(x) cos(x) + 2 cos(x) (-sin(x)) = 2 sin(x) cos(x) - 2 cos(x) sin(x) = 0 Since the derivative is zero everywhere the function must be a constant. Take f(0) = sin^2(0) + cos^2(0) = 0 + 1 = 1 So sin^2(x) + cos^2(x) = 1 |
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