1.

2tan AIf cosAs-xī, then find the values of sinA and tanA in terms of x.

Answer»

we know,cos A = B/H = 2x/1 + x^2

Using pythagoras theoram H^2 = P^2 + B^2 (1 + x^2) = P^2 + 4x^2 1 + x^4 + 2x^2 = P^2 + 4x^2 P^2 = 1 + x^4 - 2x^2 P^2 = (1 - x^2)^2 P = (1 - x^2)

Therefore,sin A = P/H = (1 - x^2)/(1 + x^2) tan A = P/B = (1 - x^2)/2x



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