1.

(2x+3) (3x-1) =?(a) (6x2+8x-3) (b) (6x2+7x-3) (c) (6x2-7x-3) (d) (6x2-7x+3)

Answer»

(b) (6x2+7x-3)

Explanation:

Given (2x+3) (3x-1)

By solving in horizontal method we get

(2x+3) (3x-1)= 2x (3x-1) + 3 (3x-1)

(2x+3) (3x-1)= (6x2+7x-3)



Discussion

No Comment Found