(2x – 3y)3 + (3y – 4z)3 + (4z – 2x)3 can be factorised into whic

1.	(2x – 3y)3 + (3y – 4z)3 + (4z – 2x)3 can be factorised into which one of the following ?(a) (2x + 3y + 4z) (2x – 3y – 4z) (b) (2x + 3y – 4z) (2x – 3y + 4z) (c) (2x – 3y) (3y – 4z) (4z – 2x) (d) 6 (2x – 3y) (3y – 4z) (2z – x)
Answer» (d) 6.(2x – 3y)(3y – 4z)(2z – x). Since (2x – 3y) + (3y – 4z) + (4z – 2x) = 0, therefore, (2x – 3y)³ + (3y – 4z)³ + (4z – 2x)³ (Take out 2 common) = 3.(2x – 3y)(3y – 4z) (4z – 2x) = 6.(2x – 3y)(3y – 4z)(2z – x).

(2x – 3y)3 + (3y – 4z)3 + (4z – 2x)3 can be factorised into which one of the following ?(a) (2x + 3y + 4z) (2x – 3y – 4z) (b) (2x + 3y – 4z) (2x – 3y + 4z) (c) (2x – 3y) (3y – 4z) (4z – 2x) (d) 6 (2x – 3y) (3y – 4z) (2z – x)

Answer»

(d) 6.(2x – 3y)(3y – 4z)(2z – x).

Since (2x – 3y) + (3y – 4z) + (4z – 2x) = 0, therefore,

(2x – 3y)³ + (3y – 4z)³ + (4z – 2x)³ (Take out 2 common)

= 3.(2x – 3y)(3y – 4z) (4z – 2x)

= 6.(2x – 3y)(3y – 4z)(2z – x).