2xx 10^(8)atoms of carbon arearranged side bysidecaculatethe radiusof carbonatom if thelengthof this arrangementis 2.4cm .

2xx 10^(8)atoms of carbon arearranged side bysidecaculatethe radiusof

1.	2xx 10^(8)atoms of carbon arearranged side bysidecaculatethe radiusof carbonatom if thelengthof this arrangementis 2.4cm .
Answer» Solution :Where`2xx 10^(8)` carbonatom = 2.4 CM 1carbonatom= (?)CAM diameter ofcarbon = `(1xx 2.4 cm)/(2xx 10^(8))= 1.2xx 10^(8) cm` radiusof carbon= `(1.2xx 10^(8) cm)/(2 ) ` `6.0 XX 10^(9) cm` `6.0 xx 10^(9) xx 10^(7) NM` `-0.06 nm`