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3.011xx10^(22) molecules are removed from a vessel Containing 1680 cc of nitrogen at STP. How many moles are remaining ? |
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Answer» Solution :Number of MOLES of `N_(2)` originally present =`("volume")/("GMV") = (1680)/(22400) = (3)/(40)` Number of moles of `N_(2)` removed = `("Number of MOLECULES")/("Avogadro number") = (3.011xx10^(22))/(6.022xx10^(23)) = (1)/(20)` Number of moles remaining `= (3)/(40)-(1)/(20) = (1)/(40) = 2.5xx10^(-2) = 0.025` |
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