1.

√3-1/√3+1=2-√3= how??Pls help

Answer» By rationalising..(√3-1/√3+1)×(√3-1/√3-1) = (√3-1)²/(√3)²-(1)²[(a+b)(a-b)=a²-b²]= (3+1-2√3)/2 [(a-b)²=a²+b²-2ab]= (4-2√3)/2= 2(2-√3)/2= 2-√3= RHS


Discussion

No Comment Found