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3.1 mol `Fe^(3+)` and 3.2 mol `"SCN"^(Theta)` present in 1 L solution. At equilibrium 3 mol `FeSCN^(2+)` are formed The equilibrium constant `K_(c)` for the reaction `Fe^(3+)+SCN^(Theta)hArrFeSCN^(2+)` willA. 150B. 400C. 300D. 250 |
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Answer» Correct Answer - A `underset(3.1)(Fe^(3+))+underset(3.2)(SCN^(Theta)) hArr FeSCN^(2+)` `3.1-1" "3.2-x" "x=3` `3.1-3=3.2-3` `=0.1=0.2` `K_(C)=(3)/(0.1xx0.2)=(300)/(2)=150` |
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