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`3.2 g` oxygen is diffused in `10 min`. In similar conditions, `2.8 g` nitrogen will diffuse inA. `9.3 min`B. `8.2 min`C. `7.6 min`D. `11.8 min` |
Answer» Rate of diffusion `prop sqrt((1)/(M))` `:. ((1)/(t_(O_(2))))/((1)/t_(N_(2)))=sqrt((M_(N_(2)))/(M_(O_(2))))=sqrt((2.8)/(3.2))=0.93` or `(t_(N_(2)))/(t_(O_(2)))=0.93` `:. T_(N_(2))=0.93xx10=9.3 min` |
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