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3.65gm equimole mixture of `NaOH` and `Na_(2)CO_(3)` is titrated against `0.1M HCl` using phenolphathalein as an indicator, `V_(1)mL` of acid was required to reach end point. In another experiment `3.65gm` of same mixture is titrated against 0.2M HCl using methyl orange as an indicator, `V_(2)mL` of acid was required to reach end point. `V_(1)+V_(2)` is :A. 875mLB. 750mLC. 500mLD. 1000mL

Answer» Correct Answer - a


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