3.65grams of HCI dissolved in 16.2g of water. The mole fraction of HCI in the resulting solution isA. `0.4`B. `0.3`C. `0.2`D. `0.1`

3.65grams of HCI dissolved in 16.2g of water. The mole fraction of HCI

1.	3.65grams of HCI dissolved in 16.2g of water. The mole fraction of HCI in the resulting solution isA. `0.4`B. `0.3`C. `0.2`D. `0.1`
Answer» Correct Answer - D `X=(n)/(n + N)` `n=(w)/(m)=(3.65)/(36.5)=0.1, N=(W)/(M)=(16.2)/(18)=0.9` `X=(0.1)/(0.1+0.9)=0.1`.

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3.65grams of HCI dissolved in 16.2g of water. The mole fraction of HCI in the resulting solution isA. `0.4`B. `0.3`C. `0.2`D. `0.1`

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