InterviewSolution
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InterviewSolution
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`3.7 gm` of gas at `25^(@)C` occupied the same volume as `0.184 gm` of hydrogen at `17^(@)C ` and at the same pressure. What is the molecular mass of the gas ? |
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Answer» For hydrogen, `w = 0.184 g , T = 17 + 273 = 290 K, M = 2` We know that, `PV = (w)/(M) RT` `= (0.184)/(2) xx R xx 290`.....(i) For unknown gas, `w = 3.7 g, T = 25 + 273 = 298 K, M = ?` `PV = (3.7)/(M) xx R xx 298`....(ii) Equating both the equations, `(3.7)/(M) xx R xx 298 = (0.184)/(2) xx R xx 290` or `M = (3.7 xx 298 xx 2)/(0.184 xx 290) = 41.33` |
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