InterviewSolution
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InterviewSolution
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3-74&”774%4&&7,%[}0! wch thol 9e=RE.ik s7_ and E. g L ssi] = i दा o dus g POES.iy, oh :e e o |देन - — — SR| % -औके का.के... - > gi |
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Answer» By mid-point theorem in (PEQ) F is the mid point of PE.[Since R is mid point of QE (QR=RE) and SR||PQ (||gm PQRS).]So =>2RF=PQ.PQ=SR (||gm)=> 2RF=SRHence F is the midpoint of SR. In (QSR) QF is the median. Hence SQF=QFR= 3cm square In || PQRS, diagonal QS divides it into two equal triangles i.e. QPS=QSR QSR= QSF+QFR=> 3+3= 6 cm square.2 ar(QSR) = ||gm PQRS (QPS=QSR) => PQRS= 12 cm square. Hence the area of parallelogram PQRS is 12 cm square. |
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