3.8 of motlesn `SnCI_(2)` is electroysed for some time using insert electrodes 0.238 g of Sn is deposited at cathode No substance is lost during the eletroysis find the ratio of weight of `SnCI_(2)` and `SnCI_(4)` after electroysis (Sn=11)

3.8 of motlesn `SnCI_(2)` is electroysed for some time using insert el

1.	3.8 of motlesn `SnCI_(2)` is electroysed for some time using insert electrodes 0.238 g of Sn is deposited at cathode No substance is lost during the eletroysis find the ratio of weight of `SnCI_(2)` and `SnCI_(4)` after electroysis (Sn=11)
Answer» `SnCI_(2)rarrSn^(+2)+2CI^(-)` `Sn^(+2)+2e^(-)rarrSn` Mass of Sn deposited =0.238 g m=Z it =ZQ Charge `Q=(m)/(z)=(mxxnxxf)/(At.wt)` `Q=(0.238)/(119)xx2xx96500` Q=386 columb For chrone `2CI^(-)rarrCI_(2)+2e` Mass `m_(CI_(2))=Zit=(71)/(nF)xxQ` `=(71)/(2xx96500)xx386=0.142 g` To calculate weight of `SnCI_(4)` produced `SnCI_(2)+CI_(2)rarrSnCI_(4)` `n_(CI_(2))/(1)=n_(SnCI_(4))/(1)` `rarr m_(SnCI_(4))/(261)=0.002` `rarrM_(SnCI_(4))=0.522 g` To calculate weightr of `SnCI_(2)` consumed `SnCI_(2)+CI_(2)rarrSnCI_(4)` `N_(SnCI_(2))/(1)=n_(CI_(2))/(1)=0.002` `M_(SnCI_(2))=0.002xx190=0.38 g` `m_(SnCI_(2))("remaining")=3.8-0.38-0.98=3.04 g` `"Weight ratio" =(SnCI_(2))/(SnCI_(4))=(3.04)/(0.522)=5.829`

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3.8 of motlesn `SnCI_(2)` is electroysed for some time using insert electrodes 0.238 g of Sn is deposited at cathode No substance is lost during the eletroysis find the ratio of weight of `SnCI_(2)` and `SnCI_(4)` after electroysis (Sn=11)

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