1.

3, Algebraic expression of an arithmetic sequence is 6n+1.(a) Write the sequence?(b) Find the remainder leaving on dividing each term by 6?(c) Write the algebraic expression of sequence of natural numberswhich leave remainder 2 on division by 6?

Answer»

(a) Put n = 1 6n + 1 = 7 Put n = 2 6n + 1 = 13 Put n = 3 6n + 1 = 19 Therefore, the sequence is 7, 13, 19, ......

(b) When each term of the sequence is divided by 6, the remainder is 1.(c) 6n + 2 is the required expression

(a) put n =16n+1=7put n=26n+1=13put n=36n+1=19Than the Sequence is 7,13,19.......



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