1.

3. Calculate the work done when 1.0 mol of water at373 K vaporizes against an atmospheric pressure of1-0 atmosphere. Assume ideal gas behaviour.

Answer»

We know,

PV=nRT

V=nRT/P

V= 1×0.0821×373/1=30.6L=30.6×10-3m3

Volume of liquid water can be taken negligible and thusΔV=30.6L

W=-PΔV=-101325×30.6×10-3m3=-3100J

Negative sign indicates that work is done by the system.



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