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\(3(cos \frac \pi6 + i \,sin \frac \pi6) = 3e^{i\frac\pi6}\) is equal to |
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Answer» \(3(cos \frac \pi6 + i \,sin \frac \pi6) = 3e^{i\frac\pi6}\) \((\because e^i\theta = cos \theta + i\, sin \theta)\) or \(3(cos \frac \pi6 + i\, sin \frac \pi 6) = 3 (\frac{\sqrt3}2 + \frac i2)\) \(= \frac 32 (\sqrt 3 + i)\) |
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