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3 equation of motion |
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Answer» Area of trapezium =½×(v+u)tS=½×(v+u)(v-u)/a [v-u/a =t]2as=v²-u²V²=u²+2as V²-u²=2asV=u+atS=ut+½at² V=u+at(velocity-time graph)S =ut+1/2at^2(position-time graph)V^2=u^2+2as(position-velocity graph) 1) first motion equation is v=u+at2) second motion equation is s=ut+1/2 at^23). Third motion equation is v^2=u^2+2as And with respect to gravity..v^2=u^2-2gs. V^2=u^2+2as... |
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