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3. Find the general solution of the differential equation : \( \frac{d y}{d x}=\frac{3 e^{2 x}+3 e^{4 x}}{e^{x}+e^{-x}} \) |
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Answer» \(\frac{dy}{dx}=\frac{3e^{2x}+3e^{4x}}{e^x+e^{-x}}\) = \(\frac{3e^{2x}(1+e^{2x})e^x}{e^{2x}+1}\) = 3e3x ⇒ dy = 3e3xdx ⇒ y = \(\frac{3e^{3x}}3+c\) ⇒ y = e3x + c is general solution of the given differential equation. |
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