1.

(3) have a vlote5.6 litre of axygen at STP contains(1) 6.02 x 1023 atoms2.(3) 1.505-102 atomsht(2) 3.01x 1022 atams(4) 0.7525% 102 atomsThen mol w. of substance is:

Answer»

Therefore,5.6 Lis occupied by 0.25 moles of a gas, which will thereforecontain0.25 x 6.023 x 10^23 particles. 1.50575 * 10^23 molecules ofOxygengas in5.6 L. One moleculecontains2atomsofoxygen, so the number ofatomsis double the number of molecules. 3.0115 * 10^23atomsofoxygenin5.6 L oxygengas.



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