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3 ’IJ ही 2 5 क प्रथम 22 पा का योग कहे |
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Answer» a = 8d = 3 - 8 = -5Sum of n terms of an A. PSn = (n/2) [2a + (n - 1)d] S₂₂ = (22/2) [2(8) + (22 - 1)(-5)] S₂₂ = 11 [16 + 21(-5)] S₂₂ = 11 [16 - 105] S₂₂ = 11 × -89 S₂₂ = -979 |
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