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3. In Fig. 6.18, if LMCB and LN | | CD, prove thatAM ANNAB AD |
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Answer» LM || CBBy using basic proportionality theorem, we get,AM/MB = AL/AC ...(i)Similarly, LN || CD∴ AN/AD = AL/AC ...(ii)From(i)and(ii), we getAM/MB = AN/AD figure is this in this question |
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