1.

3 mole of A and 4 moles of B are mixed together and allowed to come into equilibrium according to the following reaction 3A_((g))+4B_((g))hArr2C_((g))+3D_((g))

Answer»

`1//4`
`1//3`
`1//2`
1

Solution :`3A+4BhArr2C+3D`
`impliesK_(1)=([C]^(2)[D]^(3))/([A]^(3)[B]^(4))""...(i)`
When moles of `C=1` the equation becomes
`3/2A+2BhArrC+3/2D`
`impliesK_(2)=([C][D]^(3//2))/([A]^(3//2)[B]^(2))""...(ii)`
On comparing Eq. (i) with Eq. (ii), we GET
`K_(2)^(2)=K_(1)^(2)or K_(2)=(K_(1))^(1//2)`
HENCE, equlibrium extent`=1/2`


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