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InterviewSolution
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3) (RT)2are equai, then percent of B reacted is(1) 10%(RT)129 For the reaction A 3B2C D, initial mole of A is twice that of B. If at equilibriummoles of B and c(2)(4)20%(3)40%60%mining equal moles of A and B in a one litre vessel |
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Answer» Here according the equation, 1 mole of A will combine with 3 mole of B and so if x mole of A is consumed then it will combine with 3x mole of B and similarly we can calculate the number of mole of C and D formed.Now from the question given that, at equilibrium, (a/2)-3x = 2x a/2= 5x, x=a/10 so amount of B reacted=3x=3a/10Initial amount of B=a/2 so % of B reacted= {3a/10}/{a/2} *100 =6/10 *100=60%Hence, option (4) is correct. |
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