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3. The value of \( \left(6^{-1}+8^{-1}\right) \times\left(\frac{5}{2}\right)^{-1} \) is(a) \( \frac{5}{28} \)(b) \( \frac{28}{5} \)(c) \( \frac{60}{7} \)(d) \( \frac{7}{60} \) |
Answer» (6-1+8-1)×(5/2)-1={(1/6)+(1/8)}×(2/5)={(4+3)/24}×(2/5) (taking the LCM of 8 and 6 which is 24)=(7/24)×(2/5)=14/120=7/60. (we get this by dividing 14 and 120 by 2) |
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