1.

30.4 KJ is required to melt one mole of sodium chloride. The entropy change during melting is 28.4 JK^(-1) mol^(-1). Calculate the melting point of sodium chloride.

Answer»

SOLUTION :GIVEN :
`delta H_(f) (NaCl) = 30.4kJ = 30400 J MOL^(-1)`
`delta S_(f) (NaCl) = 28.4 JK^(-1) mol^(-1)`
`T_(f) = ?`
`DeltaS_(f) = (Delta H_(f))/(Delta T_(f)) , T_(f) = (Delta H_(f))/(Delta S_(f))`
`T_(f) = (30400 J mol^(-1))/(28.4 J K^(-1) mol^(-1)) = 1070.4K`


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