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30.4 KJ is required to melt one mole of sodium chloride. The entropy change during melting is 28.4 JK^(-1) mol^(-1). Calculate the melting point of sodium chloride. |
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Answer» SOLUTION :GIVEN : `delta H_(f) (NaCl) = 30.4kJ = 30400 J MOL^(-1)` `delta S_(f) (NaCl) = 28.4 JK^(-1) mol^(-1)` `T_(f) = ?` `DeltaS_(f) = (Delta H_(f))/(Delta T_(f)) , T_(f) = (Delta H_(f))/(Delta S_(f))` `T_(f) = (30400 J mol^(-1))/(28.4 J K^(-1) mol^(-1)) = 1070.4K` |
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