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30.4 KJ is required to melt one mole of sodium chloride. The entropy change during melting is 28.4 JK^(-1) mol^(-1). Calculate the melting point of sodium chloride.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> : <br/> `delta H_(f) (NaCl) = 30.4kJ = 30400 J <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>^(-1)` <br/> `delta S_(f) (NaCl) = 28.4 JK^(-1) mol^(-1)` <br/> `T_(f) = ?` <br/> `DeltaS_(f) = (Delta H_(f))/(Delta T_(f)) , T_(f) = (Delta H_(f))/(Delta S_(f))` <br/> `T_(f) = (30400 J mol^(-1))/(28.4 J <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>^(-1) mol^(-1)) = 1070.4K`</body></html>


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