30 (a2bc + ab2c + abc2) ÷ 6abc = ……………… A) 5 (a + b + c)

1.	30 (a2bc + ab2c + abc2) ÷ 6abc = ……………… A) 5 (a + b + c) B) 6 (a + b) C) a + b + c D) 3 (a – b)
Answer» A) 5 (a + b + c) Correct option is (A) 5 (a + b + c) \(30\,(a^2bc+ab^2c+abc^2)\div6abc\) \(=\frac{30\,(a^2bc+ab^2c+abc^2)}{6abc}\) \(=\frac{30abc(a+b+c)}{6abc}\) = 5 (a + b + c)

30 (a2bc + ab2c + abc2) ÷ 6abc = ……………… A) 5 (a + b + c) B) 6 (a + b) C) a + b + c D) 3 (a – b)

Answer»

A) 5 (a + b + c)

Correct option is (A) 5 (a + b + c)

\(30\,(a^2bc+ab^2c+abc^2)\div6abc\) \(=\frac{30\,(a^2bc+ab^2c+abc^2)}{6abc}\)

\(=\frac{30abc(a+b+c)}{6abc}\)

= 5 (a + b + c)