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30 g of sugar was mixed in 180 ml water in a vessel A, 40 g of sugar was mixed in 280 ml of water in vessel B and 20 g of sugar was mixed in 100 ml of water in vessel C. The solution in vessel B is:1. sweeter than that in C2. Sweeter than that in A3. as sweet as that in C4. less sweet than that in C |
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Answer» Correct Answer - Option 4 : less sweet than that in C Given Vessel A, sugar = 30 g, water = 180 ml Vessel B, sugar = 40 g, Water = 280 ml Vessel C, Sugar = 20g , water = 100 ml Calculation ⇒ Concentration of sugar in vessel A = 30/180 = 1/6 g/ml ⇒ Concentration of sugar in vessel B = 40/280 = 1/7 g/ml ⇒ Concentration of sugar in vessel C = 20/100 = 1/5 g/ml ⇒ the more concentration of sugar means more sweetness of solution ⇒ vessel C > vessel A > vessel B ∴ the solution of B is less sweet than solution C
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