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30mL of mixture of methane and ethane in x : y ratio of volumes on combustioin gave 40mL of carbon dioxide. If 30mL of mixture is taken in y:x ratio, what is the volume of carbondioxide obtained under similar conditions? |
Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/combustion-13975" style="font-weight:bold;" target="_blank" title="Click to know more about COMBUSTION">COMBUSTION</a> of methane and ethane is given by the equations <br/> `CH_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) overset(O_(2))to CO_(2)+2H_(2)O`: <br/> `C_(2)H_(6) overset(O_(2))to 2CO_(2)+3H_(2)O` <br/> 1 volume of `CH_(4)="1 volume of "CO_(2)` <br/> 1 volume of `C_(2)H_(6)="2 volume of "CO_(2)` <br/> Let, Volume of `CH_(4)` in the given mixture=x <br/> Let, volume of `C_(2)H_(6)` in the given mixture=y <br/> Then, x+y=30 `""` x+2y=40 <br/> `"y=10"x=30-10=20` <br/> If y mL of `CH_(4)` is taken <br/> the volume of `CO_(2)` obtained =y=10mL <br/> If x mL of `C_(2)H_(6)` is taken <br/> the volume of `CO_(2)` obtained =2x=2 x 20=40mL <br/> The volume of <a href="https://interviewquestions.tuteehub.com/tag/carbondioxide-413336" style="font-weight:bold;" target="_blank" title="Click to know more about CARBONDIOXIDE">CARBONDIOXIDE</a> obtained by the combustion of 30mL of y:x volumes of methane and ethane =10+40=50mL</body></html> | |