30mL of mixture of methane and ethane in x : y ratio of volumes on combustioin gave 40mL of carbon dioxide. If 30mL of mixture is taken in y:x ratio, what is the volume of carbondioxide obtained under similar conditions?

30mL of mixture of methane and ethane in x : y ratio of volumes on com

1.	30mL of mixture of methane and ethane in x : y ratio of volumes on combustioin gave 40mL of carbon dioxide. If 30mL of mixture is taken in y:x ratio, what is the volume of carbondioxide obtained under similar conditions?
Answer» Solution :The COMBUSTION of methane and ethane is given by the equations `CH_(4) overset(O_(2))to CO_(2)+2H_(2)O`: `C_(2)H_(6) overset(O_(2))to 2CO_(2)+3H_(2)O` 1 volume of `CH_(4)="1 volume of "CO_(2)` 1 volume of `C_(2)H_(6)="2 volume of "CO_(2)` Let, Volume of `CH_(4)` in the given mixture=x Let, volume of `C_(2)H_(6)` in the given mixture=y Then, x+y=30 `""` x+2y=40 `"y=10"x=30-10=20` If y mL of `CH_(4)` is taken the volume of `CO_(2)` obtained =y=10mL If x mL of `C_(2)H_(6)` is taken the volume of `CO_(2)` obtained =2x=2 x 20=40mL The volume of CARBONDIOXIDE obtained by the combustion of 30mL of y:x volumes of methane and ethane =10+40=50mL