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317) Find the values of p and q for which andχ#-2are the roots ofthe equation pr.gx-620.32 |
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Answer» f(x)=px^2 +qx -6=0f(3/4)=p(3/4)^2 +q(3/4) -6=0=>9p/16 + 3q/4 -6=0=>9p +12q=96.....(1)f(-2)=p(-2)^2+q(-2)-6=04p-2q=6........(2)(2)×6 => 24p -12q =36....(3)(1)+(3)33p =132p=4then q=5 |
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